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鸡尾酒排序

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鸡尾酒排序
使用鸡尾酒排序为一列数字进行排序的过程
概况
类别排序算法
数据结构数组
复杂度
平均时间复杂度
最坏时间复杂度
最优时间复杂度
最佳解No
相关变量的定义

鸡尾酒排序(英语:Cocktail shaker sort),亦为定向冒泡排序鸡尾酒搅拌排序搅拌排序(也可以视作选择排序的一种变形),涟漪排序来回排序快乐小时排序,是冒泡排序的一种变形。此算法与冒泡排序的不同处在于排序时是以双向在序列中进行排序。

伪代码

将一个序列由小到大进行排序:

function cocktail_sort(list, list_length){ // the first element of list has index 0
    bottom = 0;
    top = list_length - 1;
    swapped = true; 
    while(swapped == true) // if no elements have been swapped, then the list is sorted
    {
        swapped = false; 
        for(i = bottom; i < top; i = i + 1)
        {
            if(list[i] > list[i + 1])  // test whether the two elements are in the correct order
            {
                swap(list[i], list[i + 1]); // let the two elements change places
                swapped = true;
            }
        }
        // decreases top the because the element with the largest value in the unsorted
        // part of the list is now on the position top 
        top = top - 1; 
        for(i = top; i > bottom; i = i - 1)
        {
            if(list[i] < list[i - 1]) 
            {
                swap(list[i], list[i - 1]);
                swapped = true;
            }
        }
        // increases bottom because the element with the smallest value in the unsorted 
        // part of the list is now on the position bottom 
        bottom = bottom + 1;  
    }
}

与冒泡排序不同的地方

鸡尾酒排序等于是冒泡排序的轻微变形。不同的地方在于从低到高然后从高到低,而冒泡排序则仅从低到高去比较序列里的每个元素。他可以得到比冒泡排序稍微好一点的性能,原因是冒泡排序只从一个方向进行比对(由低到高),每次循环只移动一个项目。

以序列(2,3,4,5,1)为例,鸡尾酒排序只需要访问一次序列就可以完成排序,但如果使用冒泡排序则需要四次。但是在随机数序列的状态下,鸡尾酒排序与冒泡排序的效率与其他众多排序算法相比均比较低。

实现示例

C语言

void cocktail_sort(int arr[], int len) {
	int i, left = 0, right = len - 1;
	int temp;
	while (left < right) {
		for (i = left; i < right; i++)
			if (arr[i] > arr[i + 1]) {
				temp = arr[i];
				arr[i] = arr[i + 1];
				arr[i + 1] = temp;
			}
		right--;
		for (i = right; i > left; i--)
			if (arr[i - 1] > arr[i]) {
				temp = arr[i];
				arr[i] = arr[i - 1];
				arr[i - 1] = temp;
			}
		left++;
	}
}

C++

template<typename T> //整數或浮點數皆可使用,若要使用物件(class)時必須設定大於(>)的運算子功能
void cocktail_sort(T arr[], int len) {
	int j, left = 0, right = len - 1;
	while (left < right) {
		for (j = left; j < right; j++)
			if (arr[j] > arr[j + 1])
				swap(arr[j], arr[j + 1]);
		right--;
		for (j = right; j > left; j--)
			if (arr[j - 1] > arr[j])
				swap(arr[j - 1], arr[j]);
		left++;
	}
}

Rust

fn cocktail_sort<T: PartialOrd>(arr: &mut [T]) {
    let mut bottom: usize = 0;
    let mut top = arr.len() - 1;
    let mut swapped = true;

    while swapped {
        swapped = false;
        for i in bottom..top {
            if arr[i] > arr[i+1] {
                arr.swap(i, i+1);
                swapped = true;
            }
        }

        top -= 1;
        for j in ((bottom + 1)..=top).rev() {
            if arr[j] < arr[j - 1] {
                arr.swap(j, j - 1);
                swapped = true;
            }
        }
        bottom += 1;
    }
}

JAVA

public static void cocktail_sort(int[] arr) {	
	int i, left = 0, right = arr.length - 1;
	int temp;
	while (left < right) {
		for (i = left; i < right; i++)
			if (arr[i] > arr[i + 1]) {
				temp = arr[i];
				arr[i] = arr[i + 1];
				arr[i + 1] = temp;
			}
		right--;
		for (i = right; i > left; i--)
			if (arr[i - 1] > arr[i]) {
				temp = arr[i];
				arr[i] = arr[i - 1];
				arr[i - 1] = temp;
			}
		left++;
	}
}

JavaScript

Array.prototype.cocktail_sort = function() {
	var i, left = 0, right = this.length - 1;
	var temp;
	while (left < right) {
		for (i = left; i < right; i++)
			if (this[i] > this[i + 1]) {
				temp = this[i];
				this[i] = this[i + 1];
				this[i + 1] = temp;
			}
		right--;
		for (i = right; i > left; i--)
			if (this[i - 1] > this[i]) {
				temp = this[i];
				this[i] = this[i - 1];
				this[i - 1] = temp;
			}
		left++;
	}
};

PHP

function swap(&$x, &$y) {
	$t = $x;
	$x = $y;
	$y = $t;
}
function cocktail_sort(&$arr) {//php的陣列視為基本型別,所以必須用傳參才能修改原陣列
	$left = 0;
	$right = count($arr) - 1;
	while ($left < $right) {
		for ($j = $left; $j < $right; $j++)
			if ($arr[$j] > $arr[$j + 1])
				swap($arr[$j], $arr[$j + 1]);
		$right--;
		for ($j = $right; $j > $left; $j--)
			if ($arr[$j - 1] > $arr[$j])
				swap($arr[$j - 1], $arr[$j]);
		$left++;
	}
}

Python 2.7

def cocktail_sort(l):
    l_len = len(l)
    for i in range(l_len, 0, -1):
        rem_i_l_len = abs(i - l_len)
        isNeedContinue = False
        obverse_count = len(l[rem_i_l_len : i-1])
        reverse_count = len(l[rem_i_l_len + 1 : i-1])
        
        for j in range(obverse_count):
            if l[j] > l[j + 1]:
                l[j], l[j + 1] = l[j + 1], l[j]
                isNeedContinue = True
        # you can print this to observe the whole process
        # print l
        
        for j in range(reverse_count, 0, -1):
            if l[j] < l[j - 1]:
                l[j], l[j - 1] = l[j - 1], l[j]
                isNeedContinue = True
        # you can print this to observe the whole process
        # print l
        
        if isNeedContinue:
            continue
        else:
            return
  
        
if __name__ == '__main__':
    sample_list = [6,5,4,3,2,100]
    cocktail_sort(sample_list)
    print(sample_list)

Python 3.10

def cocktail_sort(arr: list, bottom: int = None, top: int = None):
    if not bottom and not top:
        bottom, top = 0, len(arr) - 1

    if bottom == top or bottom > top:
        return

    swapped: bool = False
    for i in range(bottom, top):
        if arr[i] > arr[i + 1]:
            arr[i + 1], arr[i] = arr[i], arr[i + 1]
            swapped = True

    for i in range(top - 1, bottom, -1):
        if arr[i] < arr[i - 1]:
            arr[i - 1], arr[i] = arr[i], arr[i - 1]
            swapped = True

    if not swapped:
        return

    cocktail_sort(arr, bottom + 1, top - 1)

if __name__ == '__main__':
    sample_list = [3, 7, 5, 1, 6, 4, 8, 2]
    cocktail_sort(sample_list)
    print(sample_list)

Golang

func cocktailSort(arr []int) {
	left := 0
	right := len(arr) - 1

	for left < right {
		for i := left; i < right; i++ {
			if arr[i] > arr[i+1] {
				arr[i], arr[i+1] = arr[i+1], arr[i]
			}
		}
		right--

		for i := right; i > left; i-- {
			if arr[i-1] > arr[i] {
				arr[i-1], arr[i] = arr[i], arr[i-1]
			}
		}
		left++
	}
}


# Julia Sample : CocktailSort

function CocktailSort(A)
	isordered, lo, hi  = false, 1, length(A)
 
	while !isordered && hi > lo
		isordered = true
		
		for i=lo+1:hi
			if A[i] < A[i-1]
				A[i-1], A[i] = A[i], A[i-1]
				isordered = false
			end
		end
		
		hi -= 1
		
		if isordered || hi  lo 
			break 
		end

		for i in hi:-1:lo+1
			if A[i-1] > A[i]
				A[i-1], A[i] = A[i], A[i-1]
				isordered = false
			end
		end
		lo += 1
	end
	return A
end

# Main Code
A = [16,586,1,31,354,43,3]
println(A)                      # Original Array
println(CocktailSort(A)) 		# Cocktail Sort Array

复杂度

鸡尾酒排序最糟或是平均所花费的次数都是,但如果序列在一开始已经大部分排序过的话,会接近

外部链接